Win a $250 Mall of America gift card and a 3-night hotel stay in Bloomington
Bloomington Minnesota Travel & Tourism is hosting a 2026 Valentine’s Day Giveaway. This delightful opportunity offers one fortunate winner a romantic getaway that includes a three-night stay for two at the Sheraton Bloomington Hotel and Lela Restaurant, in addition to a $200 gift card for the Mall of America, applicable at participating stores, restaurants, and attractions.
How to Enter
The giveaway is set to take place from January 8, 2026, at 12:00 a.m. Central Time until February 11, 2026, at 11:59 p.m. Central Time. Participants who are at least 21 years old and reside in the United States or Canada (excluding Quebec) can enter by filling out the online entry form available on the official giveaway website. Entry requires basic contact information and an answer to a hotel-related question, with only one entry permitted per person each day.
A winner will be randomly chosen around February 12, 2026, and will be notified via email. This individual must meet specific verification requirements, including completing necessary forms and providing valid identification. The prize must be redeemed on dates specified by the sponsor, and any additional travel costs or taxes incurred will be the responsibility of the winner.
For further details and instructions on how to enter, visit the Bloomington Minnesota Travel & Tourism website.
